5.如图,∠BCD=95°,AB∥DE,则∠α与∠β满足( )
A. ∠α+∠β=95° B. ∠β﹣∠α=95° C. ∠α+∠β=85° D. ∠β﹣∠α=85°
A. ∠α+∠β=95° B. ∠β﹣∠α=95° C. ∠α+∠β=85° D. ∠β﹣∠α=85°
5.解:过点C作CF∥AB
∵AB∥DE,CF∥AB
∴AB∥DE∥CF
∴∠BCF=∠α
∠DCF+∠β=180°
∴∠BCD=∠BCF +∠DCF
∴∠α+180°-∠β=95°
∴∠β﹣∠α=85°
故答案为:D